oracle 关于表中重复记录的处理

一、查询某个字段重复

select *
from User u
where u.user_name in (select
u.user_name
from User u
group by u.user_name having count(*) > 1)

二,删除表中某几个字段的重复

例:表中有条六条记录。 其中张三和王五 的记录有重复
TableA
id
customer PhoneNo
001 张三 777777
002 李四 444444
003 王五 555555
004 张三
777777
005 张三 777777
006 王五 555555
如何写一个sql语句将TableA变成如下
001 张三
777777
002 李四 444444
003 王五 555555

--测试环境
create table TableA (
id varchar(3),customer varchar(5),PhoneNo varchar(6))
insert into TableA
select '001','张三','777777'
union all select '002','李四','444444'
union all
select '003','王五','555555'
union all select '004','张三','777777'
union all
select '005','张三','777777'
union all select
'006','王五','555555'

--结果

delete TableA from TableA T
where

exists(
select 1 from tablea where customer=T.customer and
phoneno=T.phoneno
and id <
tt.id

)

--总结

该方法适用于有一个字段为自增性,例如本例中的:id

delete 表名
from 表名 as T where

exists(
select 1 from 表名 where 字段A=T.字段A and
字段B=T.字段B,(....)
and 自增列 <
T.自增列

)

三,查询并删除重复记录的SQL语句

查询及删除重复记录的SQL语句
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select
* from people
where peopleId in (select peopleId from people group by
peopleId having count(peopleId) >
1)
2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from
people
where peopleId in (select peopleId from people group by peopleId
having count(peopleId) > 1)
and rowid not in (select min(rowid) from
people group by peopleId having count(peopleId
)>1)

注:rowid为oracle自带不用该.....

3、查找表中多余的重复记录(多个字段)
select *
from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae
group by peopleId,seq having count(*) >
1)
4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from vitae a
where
(a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq
having count(*) > 1)
and rowid not in (select min(rowid) from vitae group
by peopleId,seq having
count(*)>1)

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae
a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by
peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from
vitae group by peopleId,seq having
count(*)>1)
(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select
Name,Count(*) From A Group By Name Having Count(*) >
1
如果还查性别也相同大则如下:
Select Name,sex,Count(*) From A Group By Name,sex Having
Count(*) > 1

(三)
方法一
declare @max integer,@id integer
declare
cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having
count(*) >; 1
open cur_rows
fetch cur_rows into @id,@max
while
@@fetch_status=0
begin
select @max = @max -1
set rowcount
@max
delete from 表名 where 主字段 = @id
fetch cur_rows into
@id,@max
end
close cur_rows
set rowcount 0
方法二
"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
  1、对于第一种重复,比较容易解决,使用
select
distinct * from
tableName
  就可以得到无重复记录的结果集。
  如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
select
distinct * into #Tmp from tableName
drop table tableName
select * into
tableName from #Tmp
drop table
#Tmp
  发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
  2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
select
identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as
autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where
autoID in(select autoID from
#tmp2)
  最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
(四)
查询重复
select
* from tablename where id in (
select id from tablename
group by
id
having count(id) > 1
)

原文地址:https://www.cnblogs.com/dogxuefeng/p/2557698.html