Currency Exchange POJ

题目链接:Currency Exchange

题意:

  钱的种类为N,M条命令,拥有种类为S这类钱的数目为V,命令为将a换成b,剩下的四个数为a对b的汇率和a换成b的税,b对a的汇率和b换成a的税,公式为(钱数-税)*汇率,问最后钱的数目是否会增多

题解:

  这是我第一道SPFA,这题算是SPFA的模板题吧。找令价值最大的最长路径。

 1 #include<cstdio>
 2 #include<iostream>
 3 #include<vector>
 4 #include<algorithm>
 5 #include<queue>
 6 #include<cstring>
 7 using namespace std;
 8 typedef pair<int,int> P;
 9 const int MAX_N = 1e3+9;
10 struct node{
11     int to;
12     double huilv,shui;
13     node(int a,double b,double c){
14         to = a;
15         huilv = b;
16         shui = c;
17     }
18 };
19 vector<node> vec[MAX_N];
20 double res[MAX_N];
21 int vis[MAX_N];
22 queue< int> que;
23 int N,M,T,nick;
24 int a,b;
25 double huilv1,huilv2;
26 double shui1,shui2;
27 double val;
28 void init()
29 {
30     memset(res,0,sizeof(res));
31     memset(vis,0,sizeof(vis));
32     while(!que.empty()) que.pop();
33     for(int i=0;i<MAX_N;i++) vec[i].clear();
34 }
35 int spfa(int x)
36 {
37     res[x] = val;
38     vis[x] = 1;
39     que.push(x);
40     while(!que.empty())
41     {
42         int t = que.front();
43         que.pop();
44         vis[t] = 0;
45         for(int i=0;i<vec[t].size();i++)
46         {
47             node temp = vec[t][i];
48 
49             //if(temp.to == 1) cout<<temp.to<<"  "<<temp.huilv<<"  "<<temp.shui<<endl;
50 
51             if(res[temp.to] < (res[t] - temp.shui)*temp.huilv)
52             {
53                 res[temp.to] = (res[t] - temp.shui)*temp.huilv;
54                 if(vis[temp.to] == 0)
55                 {
56                     que.push(temp.to);
57                     vis[temp.to] = 1;
58                 }
59             }
60             if(res[x] > val)
61             return 1;
62         }
63 
64     }
65     //cout<<"......."<<res[2]<<endl;
66     return 0;
67 }
68 int main()
69 {
70     while(~scanf("%d%d%d%lf",&N,&M,&nick,&val))
71     {
72         init();
73         for(int i=0;i<M;i++)
74         {
75             scanf("%d%d%lf%lf%lf%lf",&a,&b,&huilv1,&shui1,&huilv2,&shui2);
76             vec[a].push_back(node(b,huilv1,shui1));
77             vec[b].push_back(node(a,huilv2,shui2));
78         }
79         if(spfa(nick))
80         {
81             cout<<"YES"<<endl;
82         }
83         else
84         {
85             cout<<"NO"<<endl;
86         }
87     }
88     return 0;
89 }

  

原文地址:https://www.cnblogs.com/doggod/p/8933800.html