【小米oj】寻找归一数字

骗分过样例,

 1 #define mm(a) memset(a,0,sizeof(a));
 2 #define max(x,y) (x)>(y)?(x):(y)
 3 #define min(x,y) (x)<(y)?(x):(y)
 4 #define Fopen freopen("1.in","r",stdin); freopen("m.out","w",stdout);
 5 #define rep(i,a,b) for(ll i=(a);i<=(b);i++)
 6 #define per(i,b,a) for(ll i=(b);i>=(a);i--)
 7 #include<bits/stdc++.h>
 8 typedef long long ll;
 9 #define PII pair<ll,ll>
10 using namespace std;
11 const int INF=0x3f3f3f3f;
12 const int MAXN=(int)2e6+5;
13 
14 int n;
15 bool ck(int n)
16 {
17     int x=n;
18     int cnt=0;
19     while(x!=1){
20         if(cnt>10000)return 0;
21         cnt++;
22         int now=0;
23         while(x){
24             now+=(x%10)*(x%10);
25             x/=10;
26         }
27         x=now;
28     }
29     return 1;
30 }
31 int main()
32 {
33     scanf("%d",&n);
34     if(ck(n))printf("true
");
35     else printf("false
");
36     return 0;
37 }

暴力出奇迹(可以开个vis数组记录然后记忆化搜索,不过懒得写了)

原文地址:https://www.cnblogs.com/dogenya/p/10816095.html