xfire1.2.6建立webservice发布接口2(client端的测试程序)

上一篇已成功发布接口,现在来测试客户端是否可以访问.

我也是在网上各种查的结果走了很多弯路,做出来了也不是很明白,等着经理讲呢

一开始我是在WebServiceServer端的项目里直接建的测试类..这样其实也可以测试,但是很不规范

 1 package com.report.client;
 2 
 3 import java.net.MalformedURLException;
 4 
 5 import org.codehaus.xfire.XFireFactory;
 6 import org.codehaus.xfire.client.XFireProxyFactory;
 7 import org.codehaus.xfire.service.Service;
 8 import org.codehaus.xfire.service.binding.ObjectServiceFactory;
 9 
10 import com.report.model.Report;
11 import com.report.service.ReportServiceHibernate;
12 
13 public class ReportServiceInsert
14 {
15     public static void main(String[] args)
16     {
17         Service srvcModel = new ObjectServiceFactory().create(ReportServiceHibernate.class);
18         XFireProxyFactory factory = new XFireProxyFactory(XFireFactory.newInstance()
19                 .getXFire());
20 
21         String URL = "http://127.0.0.1:8080/ExtWS/service/ReportServiceHibernate";
22         try
23         {
24             ReportServiceHibernate service = (ReportServiceHibernate) factory.create(srvcModel,URL);
25 
26             Report report = new Report("1" , "1" , "1" , "1");
27             
28             service.insert(report);
29 
30         }
31         catch (MalformedURLException e)
32         {
33             e.printStackTrace();
34         }
35     }
36 }

这样可以测试成功

规范的步骤应该是:

1.建立新java project(ExtClient),导入XFire1.2 Core Libraries和XFire1.2 Http Client Libraries

2.将com.report.model/form/service层考进来(service只考interface就行了, form类不要继承ActionForm)

3.新建com.report.client包将刚才的测试类考进来就OK了.

这里只提供了流程,具体意义还需要研究