POJ 1102

Description

A friend of you has just bought a new computer. Until now, the most powerful computer he ever used has been a pocket calculator. Now, looking at his new computer, he is a bit disappointed, because he liked the LC-display of his calculator so much. So you decide to write a program that displays numbers in an LC-display-like style on his computer.

Input

The input contains several lines, one for each number to be displayed. Each line contains two integers s, n (1 <= s <= 10, 0 <= n <= 99 999 999), where n is the number to be displayed and s is the size in which it shall be displayed.

The input file will be terminated by a line containing two zeros. This line should not be processed.

Output

Output the numbers given in the input file in an LC-display-style using s "-" signs for the horizontal segments and s "|" signs for the vertical ones. Each digit occupies exactly s+2 columns and 2s+3 rows. (Be sure to fill all the white space occupied by the digits with blanks, also for the last digit.) There has to be exactly one column of blanks between two digits.

Output a blank line after each number. (You will find a sample of each digit in the sample output.)

Sample Input

2 12345
3 67890
0 0

Sample Output

      --   --        -- 
   |    |    | |  | | 
   |    |    | |  | | 
      --   --   --   -- 
   | |       |    |    |
   | |       |    |    |
      --   --        -- 

 ---   ---   ---   ---   --- 
|         | |   | |   | |   |
|         | |   | |   | |   |
|         | |   | |   | |   |
 ---         ---   --- 
|   |     | |   |     | |   |
|   |     | |   |     | |   |
|   |     | |   |     | |   |
 ---         ---   ---   ---

Source

Mid-Central European Regional Contest 1999

看看sample input和sample output就知道它让你干嘛了……所以一行行暴力一点的输出就好

 1 #include<stdio.h>
 2 #include<string.h>
 3 void row_0(int n){int i;for(i=1;i<=n+2;i++) printf(" ");}
 4 void row_1(int n){int i;printf(" ");for(i=1;i<=n;i++) printf("-");printf(" ");}
 5 void col_l(int n){int i;printf("|");for(i=1;i<=n+1;i++) printf(" ");}
 6 void col_r(int n){int i;for(i=1;i<=n+1;i++) printf(" ");printf("|");}
 7 void col_b(int n){int i;printf("|");for(i=1;i<=n;i++) printf(" ");printf("|");}
 8 void display(int num[],int n)
 9 {
10     int r,c,i;
11     for(r=1;r<=2*n+3;r++){
12         //输出三个衡横行 
13         if((r-1)%(n+1)==0)
14         for(c=0;num[c]>=0;c++){
15             if(num[c]==2 || num[c]==3 || num[c]==5 || num[c]==6 || num[c]==8 || num[c]==9) row_1(n);
16             if(num[c]==1) for(i=1;i<=n+2;i++) printf(" ");
17             if(num[c]==4){
18                 if((r-1)/(n+1)==1) row_1(n);
19                 else row_0(n);
20             }
21             if(num[c]==7){
22                 if((r-1)/(n+1)==0) row_1(n);
23                 else row_0(n);
24             }
25             if(num[c]==0){
26                 if((r-1)/(n+1)==1) row_0(n);
27                 else row_1(n);
28             }
29             printf(" ");
30         }
31         //输出上竖行 
32         if(r>1 && r<n+2)
33         for(c=0;num[c]>=0;c++){
34             if(num[c]==5 || num[c]==6) col_l(n);
35             if(num[c]==1 || num[c]==2 || num[c]==3 || num[c]==7) col_r(n);
36             if(num[c]==4 || num[c]==8 || num[c]==9 || num[c]==0) col_b(n);
37             printf(" ");
38         }
39         //输出下竖行 
40         if(r>n+2 && r<2*n+3)
41         for(c=0;num[c]>=0;c++){
42             if(num[c]==2) col_l(n);
43             else if(num[c]==0 || num[c]==6 || num[c]==8) col_b(n);
44             else col_r(n);
45             printf(" ");
46         }
47         
48         printf("
");
49     }
50 }
51 int main()
52 {
53     int i,n,num[9];char temp[9];
54     while( scanf("%d %s",&n,&temp) && n!=0 ){
55         memset(num,-1,sizeof(num));
56         for(i=0;temp[i];i++){
57             num[i]=temp[i]-'0';
58         }
59         display(num,n);
60         if(n!=0) printf("
");
61     }
62 }