joj2308

 贪心,弄个2重循环,每次取最优就可以了。

#include<iostream>
#include<stdio.h>
#include<math.h>
#include <algorithm>
using namespace std;
int a[52];
int main()
{
    int n,k;
    while(scanf("%d%d",&n,&k)!=EOF)
    {
        int i,j;
        for(i=1;i<=n;i++)
        {
            scanf("%d",&a[i]);
        }
        int mark=0,maxx=10000,j1,j2;
        for(i=1;i<=n-1;i++)
           for(j=i+1;j<=n;j++)
           {
               if(fabs(a[i]-a[j])>=k)
               {
                  mark=1;
                  int a=min(i,j);
                  int b=max(i,j);
                  if(maxx==max(i,j))
                  {
                      if((a/2+1+(b-a+1)/2)<(j1/2+1+(j2-j1+1)/2))
                      {
                          j1=a;
                          j2=b;
                      }
                  }
                  else if(maxx>max(i,j))
                  {
                      maxx=max(i,j);
                      j1=min(i,j);
                      j2=max(i,j);
                  }
               }
           }
        if(mark==0)
           printf("%d\n",n);
        else
           printf("%d\n",j1/2+1+(j2-j1+1)/2);
    }
}

原文地址:https://www.cnblogs.com/dchipnau/p/4985950.html