HttpGet params not being sent httpget.setParams(params)不好使

错误的代码

HttpClient httpclient = new DefaultHttpClient();
HttpUriRequest request = new HttpGet(uri);

HttpParams p = new BasicHttpParams();
p.setParameter("param", "value");
request.setParams(p);

request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");

HttpResponse response = null;

try {
    response = httpclient.execute(request);
} catch (ClientProtocolException e) {
    e.printStackTrace();
}

解决方案

HttpClient httpclient = new DefaultHttpClient();

String url = "http://example.com";
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add( new BasicNameValuePair( "param", "value" ) );
URI uri = new URI( url + "?" + URLEncodedUtils.format( params, "utf-8" );

HttpUriRequest request = new HttpGet(uri);

request.setHeader("Accept", "application/json, text/javascript, */*; q=0.01");

HttpResponse response = null;

try {
    response = httpclient.execute(request);
} catch (ClientProtocolException e) {
    e.printStackTrace();
}
原文地址:https://www.cnblogs.com/daxin/p/3748052.html