怎么找出标注中没有任何目标的图片?

脚本:

#!/bin/bash

for xml in `ls *.xml`
    do
        if  `grep -q "object" $xml` ;then
           echo "$xml正常"
        else
           echo "$xml不存在object标签,已删除!"
           #png=`grep "filename"|awk -F '>' '{print $2}'|sed 's#filename##g'|sed 's#<##g'|sed 's#/##g'`
                   name=`echo $xml|awk -F '.' '{print $1}'`
                   #rm -f $xml
                   #rm -f $png
                   rm -f "$name".*
                fi
    done
原文地址:https://www.cnblogs.com/datou-swag/p/13696821.html