Partition List

 1 class Solution {
 2 public:
 3     ListNode* partition(ListNode* head, int x) {
 4    // ListNode *node1,* node2;
 5     ListNode *node1,*node2;
 6     ListNode *p1=node1 , *p2=node2 ;
 7     while (head) {
 8         if (head->val < x)
 9             p1 = p1->next = head;
10         else
11             p2 = p2->next = head;
12         head = head->next;
13     }
14     p2->next = NULL;
15     p1->next = node2->next;
16     return node1->next;
17 }
18     
19 };思路比较巧
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原文地址：https://www.cnblogs.com/daocaorenblog/p/4885187.html