python课堂整理36-----组合

类跟类之间没有共同点，但是有关联，所以要用组合来解决

例如：学校、老师、课程 ，它们是完全不同的事物，但是，学校有老师，老师教课程给学生，即有关联

class School:
    def __init__(self, name, addr):
        self.name = name
        self.addr = addr

    def re_student(self):
        print('%s正在招生'%self.name)

class Teacher:
    def __init__(self,name, gender, age):
        self.name = name
        self.gender = gender
        self.age = age



class Course:
    def __init__(self, name, price, period,school,teacher):
        self.name = name
        self.price = price
        self.period = period
        self.school = school  #这里的school指实例或对象
        self.teacher = teacher  #这里的teacher指实例或对象


s1 = School('河南工业大学', '郑州')
s2 = School('北京大学', '北京')
s3 = School('上海大学', '上海')
t1 = Teacher('卢明霞', 'woman','26')
t2 = Teacher('乔某某','woman','58')
t3 = Teacher('周某某', 'male', '21')

msg = '''
1 河南工业大学
2 北京大学
3 上海大学
'''
msg2 = '''
1 卢明霞
2 乔某某
3 周某某
'''
while True:
    print(msg)
    menu = {
        '1':s1,
        '2':s2,
        '3':s3
    }

    choice = input("请选择学校:")
    school_obj = menu[choice]
    print(msg2)
    menu2 = {
        '1':t1,
        '2':t2,
        '3':t3
    }
    choice2 = input("请选择老师:")
    teacher_obj = menu2[choice2]

    name = input('课程名:')
    price = input('课程费用:')
    period = input('课程周期:')

    new_course = Course(name, price, period, school_obj, teacher_obj)
    print('课程[%s]属于%s%s'%(new_course.name, new_course.school.name, teacher_obj.name))