UVA 11584 一 Partitioning by Palindromes

Partitioning by Palindromes

Time Limit:1000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu

 
 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <algorithm>
 4 using namespace std;
 5 
 6 char a[1005];
 7 
 8 int C(int x,int y)
 9 {
10     int flg=1;
11     while(x<y)
12     {
13         if(a[x]!=a[y])
14         {
15             flg=0;
16             break;
17         }
18         x++,y--;
19     }
20     return flg;
21 }
22 
23 int main()
24 {
25     int T;
26     int dp[1005];
27     scanf("%d",&T);
28     while(T--)
29     {
30         int n,i,j;
31         scanf("%s",a);
32         memset(dp,0,sizeof(dp));
33         n=strlen(a);
34         dp[0]=1;
35         for(i=1;i<n;i++)
36         {
37             dp[i]=dp[i-1]+1;
38             for(j=i-1;j>0;j--)
39             {
40                 if(C(j,i))
41                 {
42                     dp[i]=min(dp[i],dp[j-1]+1);
43                 }
44             }
45             if(C(0,i))
46                 dp[i]=1;
47         }
48         /*for(i=0;i<n;i++)
49             printf("%d ",dp[i]);
50         printf("
");*/
51         printf("%d
",dp[n-1]);
52     }
53     return 0;
54 }
View Code
原文地址:https://www.cnblogs.com/cyd308/p/4771565.html