# 145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145.
# Find the sum of all numbers which are equal to the sum of the factorial of their digits.
# Note: as 1! = 1 and 2! = 2 are not sums they are not included.
import time
start = time.time()
L = []
def integers():
i = 3
while True:
yield i
i += 1
def factorial(n):
c = 1
for i in range(2, n+1):
c *= i
return c
integer = integers()
for i in integer:
if i < len(str(i)) * factorial(9):
if i == sum([factorial(int(k)) for k in str(i)]):
L.append(i)
else:
continue
else:
break
print "%s found in %s seconds" % (sum(L), time.time() - start)