方阵乘法、快速幂

 1 #include<cstdio>
 2 #include<cstring>
 3 const int maxn = 100;
 4 typedef struct{
 5    long long Mat[maxn][maxn];
 6 }MAT;
 7 long long MOD,d; // d是方阵的行数或者列数
 8 // 方阵的乘法,模MOD
 9 MAT mul(MAT a,MAT b){
10    MAT c;
11    memset(c.Mat,0,sizeof(c.Mat));
12    for(int i = 1 ; i <= d ; i++)
13    for(int j = 1 ; j <= d ; j++)
14    for(int k = 1 ; k <= d ; k++)
15    c.Mat[i][j] = (c.Mat[i][j] + a.Mat[i][k] * b.Mat[k][j]) % MOD;
16    return c;
17 }
18 // 方阵快速幂
19 MAT Quick_pow(MAT a,long long b){
20    MAT c; memset(c.Mat,0,sizeof(c.Mat));
21    for(int i = 1 ; i <= d ; i++) c.Mat[i][i] = 1;
22    while(b){
23       if(b & 1) c = mul(c,a);
24       a = mul(a,a);
25       b >>= 1;
26    }
27    return c;
28 }
原文地址:https://www.cnblogs.com/cyb123456/p/5827976.html