最接近原点的 K 个点

最粗暴的方法,自定义数据结构+重新定义排序规则

class Solution {
    public int[][] kClosest(int[][] points, int K) {
        int m = points.length;
        Node[] nodes = new Node[m];
        for(int i=0;i<m;i++){
            nodes[i] = new Node(points[i][0],points[i][1]);
        }
        Arrays.sort(nodes,(l,r)->{
            if(l.x * l.x + l.y * l.y > r.x * r.x + r.y * r.y) return 1;
            return -1;
        });
        int[][] res = new int[K][2];
        for(int i=0;i<K;i++){
            res[i][0] = nodes[i].x;
            res[i][1] = nodes[i].y;
        }
        return res;

    }

}


class Node{
    public int x;
    public int y;
    Node(int x,int y){
        this.x = x;
        this.y = y;
    }
}

原文地址:https://www.cnblogs.com/cstdio1/p/13949052.html