学习笔记二叉树排序,面试经常考的题目

二叉树代码

代码
using System;

namespace System.MySortNS
{
//表示二叉树,所有树节点根据严格的二叉规则聚合得到的集合
public sealed class BinaryTree
{
//二叉树节点
sealed class TreeNode
{
private int _nodevalue;//节点值
private TreeNode _leftnode;//左子节点
private TreeNode _rightnode;//右子节点

public TreeNode(int nodevalue)
{
this._nodevalue = nodevalue;
this._leftnode = null;
this._rightnode = null;
}
public int NodeValue
{
get
{
return this._nodevalue;
}
}
public TreeNode LeftNode
{
get
{
return this._leftnode;
}
set
{
if (value != null)
{
if (this.LeftNode == null)
{
this._leftnode = value;
}
else
{
//nothing to do here!
}
}
else
{
//nothing to do here!
}
}
}
public TreeNode RightNode
{
get
{
return this._rightnode;
}
set
{
if (value != null)
{
if (this.RightNode == null)
{
this._rightnode = value;
}
else
{
//nothing to do here!
}
}
else
{
//nothing to do here!
}
}
}
}

private TreeNode _rootnode;//根节点

public BinaryTree()
{
this._rootnode = null;
}

public void AddNumber(int num)
{
if (this._rootnode == null)//尚未有根节点时,新节点自然占据根节点的地位
{
this._rootnode = new TreeNode(num);
}
else
{
TreeNode newnode
= new TreeNode(num);
TreeNode currentnode
= this._rootnode;
this.addTreeNode(newnode, currentnode);
}
}
//递归方法,在已存在的树中寻找新节点的合理位置并添加
//需要了解的数据:待添加节点,当前操作到的节点
//添加规则:与当前节点比较,小向左,大向右,先来着为大
private void addTreeNode(TreeNode node,TreeNode currentnode)
{
if (node.NodeValue <= currentnode.NodeValue)//后来者为小,向左走
{
if (currentnode.LeftNode == null)
{
currentnode.LeftNode
= node;
//done!
}
else//转换比较场地,继续递归比较
{
this.addTreeNode(node,currentnode.LeftNode);
}
}
else//后来者大了,向右走
{
if (currentnode.RightNode == null)
{
currentnode.RightNode
= node;
//done!
}
else//转换比较场地,继续递归比较
{
this.addTreeNode(node, currentnode.RightNode);
}
}
}

//使用中序遍历,获取已添加的二叉树之有序节点值结果
public System.Collections.Generic.List<int> GetSortedList()
{
System.Collections.Generic.List
<int> list;
list
= new System.Collections.Generic.List<int>();
//递归进行中序遍历,获取有序数据,填充到已定义的动态数组中
TreeNode currentnode = this._rootnode;
this.fillNumber(currentnode, list);

return list;
}
//递归中序遍历填充方法
private void fillNumber(TreeNode currentnode, System.Collections.Generic.List<int> list)
{
if (currentnode != null)
{
//递归遍历左分支
this.fillNumber(currentnode.LeftNode, list);
//访问并填充当前节点值
list.Add(currentnode.NodeValue);
//递归遍历右分支
this.fillNumber(currentnode.RightNode, list);
}
else//下级节点为空,不予继续处理本次分支
{
//nothing to do here!
}
}
}

class Program
{
static void Main(string[] args)
{
string input = null;
Console.WriteLine(
"请逐次输入希望参与排序的整数,输入EXIT则结束!");
int num = 0;

BinaryTree tree
= new BinaryTree();
while (true)
{
Console.Write(
"请输入整数:");
input
= Console.ReadLine();
if (input.Trim().ToUpper() == "EXIT")
{
Console.WriteLine(
"添加结束!");
break;
}
else
{
//nothing to do here!
}
num
= Int32.Parse(input);
tree.AddNumber(num);
}
Console.WriteLine(
"如想要看到排序后的列表,请回车!");
Console.ReadLine();
Console.Write(
"\n---------------------------\n");
System.Collections.Generic.List
<int> result = tree.GetSortedList();
foreach (int n in result)
{
Console.Write(n.ToString());
Console.Write(
"\t");
}
Console.Write(
"\n---------------------------\n");
}
}
}
原文地址:https://www.cnblogs.com/cs_net/p/1837971.html