数论学习笔记

数论证明作业

T1

证明:任意奇数的平方减一是(8)的倍数
证明 :
设一奇数(x)(2n+1)
( herefore x^2-1=4n^2+4n)
(ecause 2mid2n)
( herefore 8mid4n^2 且 8mid4n)
( herefore 8mid x^2-1)

T2

证明:当(n)时偶数时,(2mid3^n+1),当(n)时奇数时,(2^2mid3^n+1),无论(n)是偶数还是奇数,对任意正整数(alpha>2)都有(2^alpha mid 3^n+1).
证明:
(ecause 2mid n)
( herefore 3^n末位为奇数,3^n+1为偶数)
( herefore 2mid 3^n+1.)

T3

(a,bin mathbb{Z}),且(b eq)

原文地址:https://www.cnblogs.com/cqbz-ChenJiage/p/13830562.html