反转一个链表并输出各个结点的值

1 typedef struct Link
2 {
3     int data;
4     struct Link* next;
5 }NODE,*pNODE;
 1 void reverse(pNODE *pphead)
 2 {
 3     pNODE pcur = *pphead, ppre = NULL, ptemp;
 4     while(pcur != NULL)
 5     {
 6         ptemp = pcur->next;
 7         pcur->next = ppre;
 8         ppre = pcur;
 9         pcur = ptemp;
10     }
11     *pphead = ppre;
12 }
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原文地址：https://www.cnblogs.com/cpsmile/p/4776854.html