Java课堂 动手动脑5

1、了解棋盘打印:利用二维数组输出一个15*15的棋盘,棋盘的原素为“+”,就是输出一个横纵都是15个“+”的二维数组,然后再以坐标形式输入棋子“●”,替换掉原来棋盘里的“+”。再编写代码。 电脑随机生成2个整数,作为电脑下棋的座标,赋给board数组。还涉及1.座标的有效性,只能是数字,不能超出棋盘范围2.如果下的棋的点,不能重复下棋。3.每次下棋后,需要扫描谁赢了

代码如下:

import java.io.*;

public class QiPan

{

//定义一个二维数组来充当棋盘

private String[][] board;

//定义棋盘的大小

private static int BOARD_SIZE = 15;

public void initBoard()

{

//初始化棋盘数组

board = new String[BOARD_SIZE][BOARD_SIZE];

//把每个元素赋为"",用于在控制台画出棋盘

for (int i = 0 ; i < BOARD_SIZE ; i++)

{

for ( int j = 0 ; j < BOARD_SIZE ; j++)

{

board[i][j] = "";

}

}

}

//在控制台输出棋盘的方法

public void printBoard()

{

//打印每个数组元素

for (int i = 0 ; i < BOARD_SIZE ; i++)

{

for ( int j = 0 ; j < BOARD_SIZE ; j++)

{

//打印数组元素后不换行

System.out.print(board[i][j]);

}

//每打印完一行数组元素后输出一个换行符

System.out.print(" ");

}

}

    public static void main(String[] args)throws Exception

    {

        QiPan gb = new QiPan();

gb.initBoard();

gb.printBoard();

//这是用于获取键盘输入的方法

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

String inputStr = null;

                System.out.println("请输入您下棋的座标,应以x,y的格式:");

//br.readLine():每当在键盘上输入一行内容按回车,刚输入的内容将被br读取到。

while ((inputStr = br.readLine()) != null)

{

//将用户输入的字符串以逗号(,)作为分隔符,分隔成2个字符串

String[] posStrArr = inputStr.split(" ");

//2个字符串转换成用户下棋的座标

int xPos = Integer.parseInt(posStrArr[0]);

int yPos = Integer.parseInt(posStrArr[1]);

//把对应的数组元素赋为""

gb.board[xPos - 1][yPos - 1] = "";

/*

 电脑随机生成2个整数,作为电脑下棋的座标,赋给board数组。

 还涉及

1.座标的有效性,只能是数字,不能超出棋盘范围

2.如果下的棋的点,不能重复下棋。

3.每次下棋后,需要扫描谁赢了

 */

gb.printBoard();

System.out.println("请输入您下棋的座标,应以x,y的格式:");

}

    }

}

2、数字转换:编写一个程序将一个整数转换为汉字读法字符串。比如1123”转换为“一千一百二十三”

代码:import java.util.Scanner;

public class ChangeRMB {  

    public static void main(String[] args) {   

     ChangeRMB t2r = new ChangeRMB();  

        String s = t2r.cleanZero(t2r.splitNum(t2r.roundString(t2r.getNum())));  

        // 如果转换过后是一个空串,则不输出屏幕  

        if(!"".equals(s)) {  

            System.out.println("转换成中文后为:" + s);  

        }   

    }  

      

    private String getNum() {  

        String s = null;  

        System.out.println("请输入一个数字(非负数,精确到小数点后两位):");  

                Scanner scanner = new Scanner(System.in);  

        s = scanner.next();  

        scanner.close();  

        return s;  

    }  

  numFormat() 方法

    private String splitNum(String s) {  

        if("".equals(s)) {  

            return "";  

        }  

        int index = s.indexOf(".");  

        String intOnly = s.substring(0, index);  

        String part1 = this.numFormat(1, intOnly);  

        String smallOnly = s.substring(index + 1);  

        String part2 = this.numFormat(2, smallOnly);  

        String newS = part1 + part2;  

        return newS;  

    }  

    private String roundString(String s) {  

        if("".equals(s)) {  

            return "";  

        }  

          int index = s.indexOf(".");  

            String intOnly = s.substring(0, index);  

             if(intOnly.length() > 13) {  

            System.out.println("输入数据过大!(整数部分最多13位!)");  

            return "";  

        }  

               String smallOnly = s.substring(index + 1);  

             if(smallOnly.length() > 2) {  

            String roundSmall = smallOnly.substring(0, 2);  

                      s = intOnly + "." + roundSmall;  

        }  

        return s;  

    }  

  

    private String numFormat(int flag, String s) {  

        int sLength = s.length();  

        String bigLetter[] = {"", "", "", "", "", "", "", "", "", ""};  

        String unit[] = {"", "", "", "", "",  "", "", "", "亿", "", "", "", ""};  

        String small[] = {"", ""};  

        String newS = "";  

        for(int i = 0; i < sLength; i ++) {  

            if(flag == 1) {  

                // 转换整数部分为中文大写形式(带单位)  

                newS = newS + bigLetter[s.charAt(i) - 48] + unit[sLength - i - 1];  

            }

            else if(flag == 2) {  

                newS = newS + bigLetter[s.charAt(i) - 48] + small[sLength - i - 1];  

            }  

        }  

        return newS;  

    }  

    

    private String cleanZero(String s) {  

        if("".equals(s)) {  

            return "";  

        }  

 

        while(s.charAt(0) == '') {  

                        s = s.substring(2);  

                       if(s.length() == 0) {  

                return "零圆";  

            }  

       }

        String regex1[] = {"零仟", "零佰", "零拾"};  

        String regex2[] = {"零亿", "零万", "零元"};  

        String regex3[] = {"亿", "", ""};  

        String regex4[] = {"零角", "零分"};  

              for(int i = 0; i < 3; i ++) {  

            s = s.replaceAll(regex1[i], "");  

        }    

               for(int i = 0; i < 3; i ++) {  

            s = s.replaceAll("零零零", "");  

            s = s.replaceAll("零零", "");  

            s = s.replaceAll(regex2[i], regex3[i]);  

        }  

                for(int i = 0; i < 2; i ++) {  

            s = s.replaceAll(regex4[i], "");  

        }  

               s = s.replaceAll("亿万", "亿");  

        return s;  

    }  

}

 

 
   

3、大数

1JDK所提供的BigInteger

2)阅读BigInteger类源码,弄清楚它是使用什么算法实现加减乘除四种运算的?

3)通过互联网查找大数运算的相关资料,给你的大数类添加乘、除、求阶乘等其它功能。

代码:package biginteger;

import java.math.BigInteger;

import java.util.Scanner;

public class Biginteger {

public static void main(String[] args) {

// TODO 自动生成的方法存根

System.out.print("请输入3个数");

Scanner input=new Scanner(System.in);

int x=input.nextInt();

BigInteger a=BigInteger.valueOf(x);

/*int y=input.nextInt();

BigInteger b=BigInteger.valueOf(y); */

BigInteger z=input.nextBigInteger();

BigInteger h=input.nextBigInteger();

System.out.print("大数的和为"+h.add(z));//大数相加

System.out.print(" 大数的差为"+h.subtract(z));//大数相减

System.out.print(" 大数的乘积为"+h.multiply(z));//大数相乘

System.out.print(" 大数相除取整为"+h.divide(z));//大数相除

System.out.print(" 大数a的绝对值为"+h.abs());//绝对值

System.out.print(" 大数的最大公约数为"+h.gcd(z));//最大公约数

System.out.print(" 大数a的相反数为"+h.negate());//取相反数

System.out.print(" 大数中较大的为"+h.max(z));//比大小(a.min(b)

System.out.print(" 大数是否相等"+h.equals(z));//比相等

System.out.println(" "+a+"!="+calculateN2(a));//阶乘

}

public static BigInteger calculateN2(BigInteger n) {

if(n.equals(1) || n.equals(0)){

return BigInteger.valueOf(1);

}

return n.multiply(calculateN2(n.subtract(new BigInteger("1"))));

}

}

截图:

.数组随机数

  1.设计思路:编写代码产生10个随机数,用数组记录,分别用消息框输出数组的下标和每个下标对应的数。通过数组计算这10个随机数的和并用消息框输出。

2程序设计流程图

代码:package random;

import java.math.BigInteger;

import javax.swing.*;

public class Random {

public static void main(String[] args) {

// TODO 自动生成的方法存根

BigInteger m=new BigInteger("100");

int c=0;

int a[]=new int [10];

 System.out.print("数组的各元素为");

for(int i=0;i<10;i++)

{

    a[i]=(int)( Math.random()*100);

    c+=a[i];

    System.out.print(a[i]+" ");

}

BigInteger b=BigInteger.valueOf(c);

String output = "";

output += "Subscript Value ";

      for ( int i = 0; i < a.length; i++ )

         output += i + " " + a[ i ] + " ";

      JTextArea outputArea = new JTextArea( 11, 10 );

      outputArea.setText( output );

      JOptionPane.showMessageDialog( null, outputArea,

         "Initializing an Array with a Declaration",

         JOptionPane.INFORMATION_MESSAGE );

          JOptionPane.showMessageDialog( null, b,

         "数组元素的和为",JOptionPane.INFORMATION_MESSAGE );

      System.exit( 0 );

      

}//时间函数System.currenttTimeMillis(),System.currentTimeMillis()

}

截图:

 

错误分析:这个程序相比来说是简单的了,在看看老师的课件,没什么问题。

原文地址:https://www.cnblogs.com/conquer-vv/p/6036840.html