JsonConvert.DeserializeObject<T>对象属性为空

解决方法:

给T类加上带参的构造函数,为成员变量赋值

一开始我的T类如下:

 public class OrderQueryParam : QueryParam
    {
        public string TypeCode { get; set; }
        public string Type { get; set; }
        public string Status { get; set; }
        public string StartTime { get; set; }
        public string EndTime { get; set; }
        public string TraderId { get; set; }
        public string Token { get; set; }
    }

JsonConvert.DeserializeObject<OrderQueryParam>反序列化后结果部分属性为Null,

后面加了个带参构造函数(如下),就得到正确结果了

public class OrderQueryParam : QueryParam
    {
        public string TypeCode { get; set; }
        public string Type { get; set; }
        public string Status { get; set; }
        public string StartTime { get; set; }
        public string EndTime { get; set; }
        public string TraderId { get; set; }
        public string Token { get; set; }

        public OrderQueryParam(string typeCode,string type,string status,string startTime,string endTime,string traderId,string token)
        {
            this.TypeCode = typeCode;
            this.Type = type;
            this.Status = status;
            this.StartTime = startTime;
            this.EndTime = endTime;
            this.TraderId = traderId;
            this.Token = token;
            
        }
    }

  

原文地址:https://www.cnblogs.com/come-on-come-on/p/8397658.html