[LeetCode] Valid Palindrome, Solution


Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
» Solve this problem

[Thoughts]
Two pointer. From both sides to middle.


[Code]
1:       bool isPalindrome(string s) {  
2: int start = 0;
3: int end = s.size()-1;
4: std::transform(s.begin(), s.end(), s.begin(), ::tolower);
5: while(start<end)
6: {
7: while(start< end && !isAlpha(s[start])) start++; //filter non-alpha char
8: while(start< end && !isAlpha(s[end])) end--; //filter non-alpha char
9: if(s[start]!=s[end]) break;
10: start++;
11: end--;
12: }
13: if(start >= end)
14: return true;
15: else
16: return false;
17: }
18: bool isAlpha(char c)
19: {
20: if(c>='a' && c<='z') return true;
21: if(c>='0' && c<='9') return true;
22: return false;
23: }


原文地址:https://www.cnblogs.com/codingtmd/p/5078901.html