「网易官方」极客战记（codecombat）攻略-游戏开发2-硬币游戏第 3 步：敌人-game-of-coins-step-3-enemies

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让我们在我们的游戏中添加一些敌人。

简介

在第三步的 Pac-Man 风格街机游戏系列中，我们会将敌人添加到游戏中。

敌人使我们的游戏变得更具挑战性，难以预测。

我们正在制作一个 “逃跑与捕捉” 式的游戏，在这种游戏中，如果敌人抓到玩家，敌人立即击败玩家

我们将使用 "one-hit" 机制，所以敌人的攻击伤害应该大于或等于玩家的最大生命值。

玩家必须避开食人魔...... 除非他们有加电（我们将在下一级创建加电）！

使用键盘或鼠标进行播放器控制：

W -> 向上
S -> 向下
A -> 左边
D -> 右边
鼠标点击 -> 移动到该点

默认代码

# 创建Pac-Man风格街机游戏的第3步。

# 游戏布局和项目。向下滚动。

game.spawnXY("forest", 16, 16)

game.spawnXY("forest", 32, 16)

game.spawnXY("forest", 48, 16)

game.spawnXY("forest", 64, 16)

game.spawnXY("forest", 16, 32)

game.spawnXY("forest", 32, 32)

game.spawnXY("forest", 48, 32)

game.spawnXY("forest", 64, 32)

game.spawnXY("forest", 16, 48)

game.spawnXY("forest", 32, 48)

game.spawnXY("forest", 48, 48)

game.spawnXY("forest", 64, 48)

game.spawnXY("bronze-coin", 16, 8)

game.spawnXY("bronze-coin", 24, 8)

game.spawnXY("bronze-coin", 32, 8)

game.spawnXY("bronze-coin", 48, 8)

game.spawnXY("bronze-coin", 56, 8)

game.spawnXY("bronze-coin", 64, 8)

game.spawnXY("bronze-coin", 72, 8)

game.spawnXY("bronze-coin", 8, 16)

game.spawnXY("bronze-coin", 24, 16)

game.spawnXY("bronze-coin", 40, 16)

game.spawnXY("bronze-coin", 56, 16)

game.spawnXY("bronze-coin", 72, 16)

game.spawnXY("bronze-coin", 8, 24)

game.spawnXY("bronze-coin", 16, 24)

game.spawnXY("bronze-coin", 24, 24)

game.spawnXY("bronze-coin", 32, 24)

game.spawnXY("bronze-coin", 40, 24)

game.spawnXY("bronze-coin", 48, 24)

game.spawnXY("bronze-coin", 56, 24)

game.spawnXY("bronze-coin", 64, 24)

game.spawnXY("bronze-coin", 72, 24)

game.spawnXY("bronze-coin", 24, 32)

game.spawnXY("bronze-coin", 56, 32)

game.spawnXY("bronze-coin", 8, 40)

game.spawnXY("bronze-coin", 16, 40)

game.spawnXY("bronze-coin", 24, 40)

game.spawnXY("bronze-coin", 32, 40)

game.spawnXY("bronze-coin", 40, 40)

game.spawnXY("bronze-coin", 48, 40)

game.spawnXY("bronze-coin", 56, 40)

game.spawnXY("bronze-coin", 64, 40)

game.spawnXY("bronze-coin", 72, 40)

game.spawnXY("bronze-coin", 8, 48)

game.spawnXY("bronze-coin", 24, 48)

game.spawnXY("bronze-coin", 40, 48)

game.spawnXY("bronze-coin", 56, 48)

game.spawnXY("bronze-coin", 72, 48)

game.spawnXY("bronze-coin", 8, 56)

game.spawnXY("bronze-coin", 16, 56)

game.spawnXY("bronze-coin", 24, 56)

game.spawnXY("bronze-coin", 32, 56)

game.spawnXY("bronze-coin", 48, 56)

game.spawnXY("bronze-coin", 56, 56)

game.spawnXY("bronze-coin", 64, 56)

game.spawnXY("bronze-coin", 72, 56)

game.spawnXY("mushroom", 40, 8)

game.spawnXY("mushroom", 8, 32)

game.spawnXY("mushroom", 72, 32)

game.spawnXY("mushroom", 40, 56)

game.score = 1000

ui.track(game, "time")

ui.track(game, "score")

# 让我们在没有能力强化的情况下简化游戏。

game.addCollectGoal(10)

game.addSurviveGoal()

player = game.spawnPlayerXY("knight", 8, 8)

player.maxSpeed = 32

def onCollect(event):

player = event.target

item = event.other

if item.type == "bronze-coin":

game.score += 1

if item.type == "mushroom":

game.score += 5

player.on("collect", onCollect)

# 在中心生成一个怪物“生成器”：

# 将生成器spawnType设置为“scout”。

# 将生成器spawnDelay设置为大于5的值

# 这个函数配置新产生的侦察兵。

def onSpawn(event):

unit = event.target

unit.maxSpeed = 8

# 将单位的攻击伤害设置为

# 大于或等于玩家的Max Health.

# 将"scout"s'"spawn"事件的处理程序设置为OnSPOWN

def checkTimeScore():

game.score -= 0.5

if game.score < 0:

game.score = 0

while True:

checkTimeScore()

# 赢得游戏胜利。

概览

敌人会给你的游戏增添刺激。

你可以在游戏中使用许多不同类型的敌人：他们可以与玩家作战，他们可以追逐和抓住玩家，或者他们可以成为竞争者（比如赛车游戏）。

如果我们使用 "generator" ，将敌人加入我们的游戏将会很简单。

但是随着时间的推移会产生敌人，所以我们应该使用 "spawn" 事件来配置它们。

目前，我们不能击败敌人，所以不需要 "defeat" 事件。另外，最好让它们变慢，否则这将是一场非常艰难的比赛。

硬币游戏第 3 步：敌人解法