JavaScript游戏——五子棋

最近半个月一直在看深入的学习JavaScript,里面有很多重点和难点,比如闭包、词法分析、面向对象等。今天给大家分享一个由JavaScript编写的五子棋游戏,主要用到JavaScript的面向对象、事件委托、闭包等知识,还是挺有分量的,正好可以检测学习的成果。

老规矩,先上图,再说话。

效果图:

这里写图片描述

五子棋素材图:

这里写图片描述

代码:

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <title>HTML五子棋游戏</title>
    <link rel="stylesheet" href="">
    <script>

        //五子棋的构造函数
        function Game(){
            this.isWin = false;//游戏是否结束标志
        }

        //闭包计棋器
        Game.cnt = (function(){
            var curr = 'black';
            return function(){
                var tmp = curr;
                if(curr == 'black'){
                    curr = 'white';
                }else{
                    curr = 'black';
                }
                return tmp;
            }
        })();

        //下棋函数
        Game.xiaQi = function(g){
            //判断选择的位置是否已经下过棋了
            if(this.style.backgroundImage.indexOf('gif') >= 0){
                alert('这里已经下过棋了');
                return ;
            }
            var color = Game.cnt();
            this.style.backgroundImage = "url(./images/"+color+".gif)";

            Game.judge.call(this,color,g);//判定函数
        }

        //判定游戏是否结束
        Game.judge = function(color,g){
            var tds = document.getElementsByTagName('td');
            //获取当前棋子所下的位置
            var curr = {x:this.cellIndex,y:this.parentElement.rowIndex,color:color};
            var line = ['','','',''];//表示当前棋子的横、竖、左斜、右斜方向的棋子

            //遍历255个棋格,看看是否能赢
            for(var i=0,tmp={};i<tds.length;i++){
                tmp = {x:tds[i].cellIndex,y:tds[i].parentElement.rowIndex,color:'0'};
                if(tds[i].style.backgroundImage.indexOf('black') >= 0){
                    tmp.color = 'b';
                }else if(tds[i].style.backgroundImage.indexOf('white') >= 0){
                    tmp.color = 'w';
                }
                //获取当前棋子的横向其他棋子的坐落情况
                if(curr.y == tmp.y){
                    line[0] += tmp.color;
                }
                //获取当前棋子的竖向其他棋子的坐落情况
                if(curr.x == tmp.x){
                    line[1] += tmp.color;
                }
                //获取当前棋子的左斜方向其他棋子的坐落情况
                if(curr.x+curr.y == tmp.x+tmp.y){
                    line[2] += tmp.color;
                }
                //获取当前棋子的右斜方向其他棋子的坐落情况
                if(curr.x-tmp.x == curr.y-tmp.y){
                    line[3] += tmp.color;
                }
            }
            color = color == 'black'?'bbbbb':'wwwww';
            //判断是否五子连珠
            for(var i=0;i<line.length;i++){
                if(line[i].indexOf(color) >=0){
                    alert('你赢了');
                    g.isWin = true;
                    break;
                }
            }
        }   

        //页面加载完成
        window.onload = function(){
            var g = new Game();
            document.getElementsByTagName('table')[0].onclick = function(ev){
                //判断是否已经赢得游戏
                if(g.isWin){
                    alert('此局已结束,请重新开始');
                    return;
                }
                Game.xiaQi.call(ev.srcElement,g);//下棋
            }

        }




    </script>
</head>
<style>
    table{
    border-collapse:collapse;   
    width:540px;
    height:540px;
    border:solid 1px blue;
    margin:auto;
    background-image: url('./images/background.gif');
}
</style>
<body>
<table>
    <tr>
        <td>&nbsp;</td>
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    </tr>
    <tr>
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</table>
</body>
</html>

今天不知道怎么搞的,写博客的时候上传不了图片,还好我机智,把图片存到GitHub上,好了,来讲代码。首先,我必须先说明一下,我觉得代码还有很大的优化空间,感兴趣的同学可以继续研究。

实现思路:首先创建一个表格,共15行,15列,把背景改成棋盘的图片,给这个table添加onclick事件,这里使用到了事件委托,事件委托我在之前的文章有介绍过,感兴趣的同学可以去看看。去调用xiaQi函数,在下棋函数中,先判断选择的位置是否已经下过棋了,使用闭包获取下一个棋子的颜色,然后调用judge函数,在函数中先获取当前棋子所下的位置,遍历255个棋格,看看是否能赢,判断是否五子连珠,如果有则游戏结束。

原文地址:https://www.cnblogs.com/cnsec/p/13407052.html