Acwing-----1015. 摘花生

算法

  • 状态表示:(f(i, j))
    集合:所有从 ((1, 1))((i, j)) 的路线
    属性:Max
  • 状态计算:集合的划分
    (f(i, j)) 根据只能向东走和向南走分为 (f(i-1, j))(f(i, j-1))

代码

#include <iostream>
using namespace std;

const int N = 110;

int T;
int n, m;
int w[N][N], f[N][N];


int main() {
    cin >> T;
    while (T--) {
        cin >> n >> m;
        for (int i = 1; i <= n; ++i) {
            for (int j = 1; j <= m; ++j) {
                cin >> w[i][j];
            }
        }
        
        for (int i = 1; i <= n; ++i) {
            for (int j = 1; j <= m; ++j) {
                f[i][j] = max(f[i - 1][j], f[i][j - 1]) + w[i][j];
            }
        }
        cout << f[n][m] << endl;
    }
    return 0;
}
``
原文地址:https://www.cnblogs.com/clown9804/p/12561404.html