cigarette

#include<iostream>
using namespace std;
int main()
{
	int N;
	cin>>N;
	while(N--)
	{
		int WholeN,k,ciga;
		cin>>WholeN>>k;
		ciga=WholeN;
		while(WholeN/k>0)
		{
			ciga+=WholeN/k;
			WholeN=WholeN%k+WholeN/k;
		}
		cout<<ciga<<endl;




	}
}
 思想非常easy。一次抽全然部烟,然后换新的烟。将留下的没有换的烟蒂和再次抽剩下的烟蒂相加再去换,直到无法再换
原文地址:https://www.cnblogs.com/clnchanpin/p/7039458.html