FZU 2104 Floor problem (水题)

 Problem 2104 Floor problem

Accept: 546    Submit: 615
Time Limit: 1000 mSec    Memory Limit : 32768 KB

 Problem Description

In this problem, we have f(n,x)=Floor[n/x]. Here Floor[x] is the biggest integer such that no larger than x. For example, Floor[1.1]=Floor[1.9]=1, Floor[2.0]=2.

You are given 3 positive integers n, L and R. Print the result of f(n,L)+f(n,L+1)+...+f(n,R), please.

 Input

The first line of the input contains an integer T (T≤100), indicating the number of test cases.

Then T cases, for any case, only 3 integers n, L and R (1≤n, L, R≤10,000, L≤R).

 Output

For each test case, print the result of f(n,L)+f(n,L+1)+...+f(n,R) in a single line.

 Sample Input

3

1 2 3

100 2 100

100 3 100

 Sample Output

0

382

332

 Source

“高教社杯”第三届福建省大学生程序设计竞赛

注意int本来是向下取整即可

#include<cstdio>
#include<cmath>
#include<cstring>
#include<stdlib.h>
#include<algorithm>
using namespace std;
int main()
{
    //freopen("in.txt","r",stdin);
    int kase;
    scanf("%d",&kase);
    while(kase--)
    {
        int n,l,r;
        int sum=0;
        scanf("%d %d %d",&n,&l,&r);
        for(int i=l;i<=r;i++)
            sum+=n/i;
        printf("%d
",sum);
    }
    return 0;
}