题面
Sol
整体二分
比较简单，当练手题
每次树状数组统计
# include <bits/stdc++.h>
# define RG register
# define IL inline
# define Fill(a, b) memset(a, b, sizeof(a))
using namespace std;
typedef long long ll;
const int _(3e5 + 5);
IL ll Input(){
RG ll x = 0, z = 1; RG char c = getchar();
for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
return x * z;
}
int n, m, k, ql[_], qr[_], qv[_], ans[_];
vector <int> son[_];
struct Data{
int id;
ll v;
} p[_], q1[_], q2[_];
ll bit[_];
IL void Modify(RG int x, RG ll v){
for(; x <= m; x += x & -x) bit[x] += v;
}
IL ll Query(RG int x){
RG ll ret = 0;
for(; x; x -= x & -x) ret += bit[x];
return ret;
}
IL void Solve(RG int l, RG int r, RG int L, RG int R){
if(L > R) return;
if(l == r){
for(RG int i = L; i <= R; ++i) ans[p[i].id] = l;
return;
}
RG int mid = (l + r) >> 1, t1 = 0, t2 = 0;
for(RG int i = l; i <= mid; ++i)
if(ql[i] <= qr[i])
Modify(ql[i], qv[i]), Modify(qr[i] + 1, -qv[i]);
else Modify(1, qv[i]), Modify(qr[i] + 1, -qv[i]), Modify(ql[i], qv[i]);
for(RG int i = L; i <= R; ++i){
RG ll sum = 0;
for(RG int j = 0, len = son[p[i].id].size(); j < len; ++j)
sum += Query(son[p[i].id][j]);
if(p[i].v <= sum) q1[++t1] = p[i];
else p[i].v -= sum, q2[++t2] = p[i];
}
for(RG int i = l; i <= mid; ++i)
if(ql[i] <= qr[i])
Modify(ql[i], -qv[i]), Modify(qr[i] + 1, qv[i]);
else Modify(1, -qv[i]), Modify(qr[i] + 1, qv[i]), Modify(ql[i], -qv[i]);
for(RG int i = L, j = 1; j <= t1; ++i, ++j) p[i] = q1[j];
for(RG int i = L + t1, j = 1; j <= t2; ++i, ++j) p[i] = q2[j];
Solve(l, mid, L, L + t1 - 1); Solve(mid + 1, r, L + t1, R);
}
int main(RG int argc, RG char* argv[]){
n = Input(); m = Input();
for(RG int i = 1; i <= m; ++i) son[Input()].push_back(i);
for(RG int i = 1; i <= n; ++i) p[i].id = i, p[i].v = Input();
k = Input();
for(RG int i = 1; i <= k; ++i)
ql[i] = Input(), qr[i] = Input(), qv[i] = Input();
ql[k + 1] = 1; qr[k + 1] = m; qv[k + 1] = 1e9;
Solve(1, k + 1, 1, n);
for(RG int i = 1; i <= n; ++i)
if(ans[i] == k + 1) puts("NIE");
else printf("%d
", ans[i]);
return 0;
}