[SCOI2007]蜥蜴

网络流
一个点拆成两个,注意要把某一类边连反过来
这样才能保证有限制

# include <bits/stdc++.h>
# define IL inline
# define RG register
# define Fill(a, b) memset(a, b, sizeof(a))
# define Copy(a, b) memcpy(a, b, sizeof(a))
# define ID(a, b) (a - 1) * c + b
# define Sqr(x) ((x) * (x))
# define Dis(i, j, x, y) (Sqr(i - x) + Sqr(j - y))
using namespace std;
typedef long long ll;

const int _(1010), __(6e6 + 10), INF(2147483647);

IL ll Read(){
    RG char c = getchar(); RG ll x = 0, z = 1;
    for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
    for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
    return x * z;
}

int num, r, c, d, high[21][21], w[__], fst[_], nxt[__], to[__], cnt, S, T, lev[_], cur[_], max_flow;
queue <int> Q;

IL void Add(RG int u, RG int v, RG int f){
    w[cnt] = f; to[cnt] = v; nxt[cnt] = fst[u]; fst[u] = cnt++;
    w[cnt] = 0; to[cnt] = u; nxt[cnt] = fst[v]; fst[v] = cnt++;
}

IL int Dfs(RG int u, RG int maxf){
    if(u == T) return maxf;
    RG int ret = 0;
    for(RG int &e = cur[u]; e != -1; e = nxt[e]){
        if(lev[to[e]] != lev[u] + 1 || !w[e]) continue;
        RG int f = Dfs(to[e], min(w[e], maxf - ret));
        ret += f; w[e ^ 1] += f; w[e] -= f;
        if(ret == maxf) break;
    }
    if(!ret) lev[u] = 0;
    return ret;
}

IL bool Bfs(){
    Fill(lev, 0); lev[S] = 1; Q.push(S);
    while(!Q.empty()){
        RG int u = Q.front(); Q.pop();
        for(RG int e = fst[u]; e != -1; e = nxt[e]){
            if(lev[to[e]] || !w[e]) continue;
            lev[to[e]] = lev[u] + 1;
            Q.push(to[e]);
        }
    }
    return lev[T];
}

int main(RG int argc, RG char* argv[]){
    r = Read(); c = Read(); d = Read(); Fill(fst, -1); T = r * c * 2 + 1;
    for(RG int i = 1; i <= r; ++i)
        for(RG int j = 1; j <= c; ++j){
            RG char cc; scanf(" %c", &cc);
            high[i][j] = (cc ^ 48);
            if(!high[i][j]) continue;
            Add(ID(i, j), ID(i, j) + r * c, high[i][j]);
            if(i <= d || j <= d || r - i < d || c - j < d) Add(ID(i, j) + r * c, T, INF);
        }
    for(RG int i = 1; i <= r; ++i)
        for(RG int j = 1; j <= c; ++j){
            RG char cc; scanf(" %c", &cc);
            for(RG int x = 1; x <= r; ++x)
                for(RG int y = 1; y <= c; ++y)
                    if((x != i || y != j) && high[x][y] && Dis(i, j, x, y) <= d * d)
                        Add(ID(i, j) + r * c, ID(x, y), INF);
            if(cc != 'L') continue;
            Add(S, ID(i, j), 1); num++;
        }
    while(Bfs()) Copy(cur, fst), max_flow += Dfs(S, INF);
    printf("%d
", num - max_flow);
    return 0;
}
原文地址:https://www.cnblogs.com/cjoieryl/p/8206354.html