20.Valid Parentheses

题目链接:https://leetcode.com/problems/valid-parentheses/description/

题目大意:简单的括号 匹配问题。

法一:栈,代码如下(耗时 9ms):

 1     public boolean isValid(String s) {
 2         char[] str = s.toCharArray();
 3         Stack<Character> stack = new Stack<Character>();
 4         for(int i = 0; i < str.length; i++) {
 5             if(str[i] == '(' || str[i] == '[' || str[i] == '{') {
 6                 stack.push(str[i]);
 7             }
 8             else if(str[i] == ')') {
 9                 if(!stack.isEmpty() && stack.pop() == '(') {
10                     continue;
11                 }
12                 else {
13                     return false;
14                 }
15             }
16             else if(str[i] == ']') {
17                 if(!stack.isEmpty() && stack.pop() == '[') {
18                     continue;
19                 }
20                 else {
21                     return false;
22                 }
23             }
24             else if(str[i] == '}') {
25                 if(!stack.isEmpty() && stack.pop() == '{') {
26                     continue;
27                 }
28                 else {
29                     return false;
30                 }
31             }
32         }
33         if(!stack.isEmpty()) {
34             return false;
35         }
36         return true;
37     }
View Code

法二(借鉴):思想略不同,更简易代码,https://leetcode.com/problems/valid-parentheses/discuss/

原文地址:https://www.cnblogs.com/cing/p/7759847.html