多继承同名隐藏举例

*/
 * Copyright (c) 2016,烟台大学计算机与控制工程学院
 * All rights reserved.
 * 文件名:text.cpp
 * 作者:常轩
 * 微信公众号:Worldhello
 * 完成日期:2016年5月19日
 * 版本号:V1.0
 * 问题描述:多继承同名隐藏举例
 * 程序输入:无
 * 程序输出:见运行结果
 */
//多继承同名举例1  通过作用域分辨符,明确地唯一标识了派生类中由基类所继承来的成员,达到了访问的目的,解决了成员被隐藏的问题
#include<iostream>
using namespace std;
class Base1{
public:
	int var;
	void fun()
	{
		cout<<"Member of Base1"<<endl;
	}
};
class Base2{
public:
	int var;
	void fun()
	{
		cout<<"Member of Base2"<<endl;
	}
};
class Derived:public Base1,public Base2{
public:
	int var;
	void fun()
	{
		cout<<"Member of Derived"<<endl;
	}
};
int main()
{
	Derived d;
	Derived* p=&d;
	d.var=1;
	d.fun();
	d.Base1::var=2;
	d.Base1::fun();
	p->Base2::var=3;
	p->Base2::fun();
	return 0;
}



运行结果:


//多继承同名举例2
#include<iostream>
using namespace std;
class Base0{
public:
	int var0;
	void fun0()
	{
		cout<<"Member of Base0"<<endl;
	}
};
class Base1:public Base0{
public:
	int var1;
};
class Base2:public Base0{
public:
	int var2;
};
class Derived:public Base1,public Base2{
public:
	int var;
	void fun()
	{
		cout<<"Member of Derived"<<endl;
	}
};
int main()
{
	Derived d;
    d.Base1::var0=2;
	d.Base1::fun0();
	d.Base2::var0=3;
    d.Base2::fun0();
	return 0;
}

运行结果:


原文地址:https://www.cnblogs.com/chxuan/p/8232214.html