HDU 2896 病毒侵袭

题目大意:比2222多输出一些东西

题解:sig别开太大了!!!HDU绝对可以MLE你到飞起。。。注意兜出去的时候判断条件要写好:

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<queue>
 6 #include<cstring>
 7 #define PAU putchar(' ')
 8 #define ENT putchar('
')
 9 using namespace std;
10 const int maxn=60000+10,sig=128;
11 struct ACauto{
12     struct node{node*ch[sig],*fail;int cnt;char x;}AC[maxn],*root;int nodecnt;
13     int id[156],ans[10001];queue<node*>RAM;
14     node*newnode(){
15         node*t;
16         if(!RAM.empty()) t=RAM.front();
17         else t=&AC[++nodecnt];
18         t->fail=root;t->cnt=0;
19         return t;
20     }
21     void init(){
22         for(int i=0;i<sig;i++) id[i]=i;
23         root=&AC[0];root->cnt=0;root->x='#';nodecnt=0;return;
24     }
25     void insert(char*s,int id){
26         int len=strlen(s);node*x=root;
27         for(int i=0;i<len;i++){
28             int c=s[i];
29             if(!x->ch[c]) x->ch[c]=newnode();
30             x=x->ch[c];x->x=s[i];
31         } x->cnt=id;return;
32     }
33     void getfail(){
34         queue<node*>Q;Q.push(root);
35         while(!Q.empty()){
36             node*x=Q.front();Q.pop();
37             for(int c=0;c<sig;c++){
38                 if(x->ch[c]){
39                     node*p=x->fail;while(p&&!p->ch[c])p=p->fail;
40                     x->ch[c]->fail=p?p->ch[c]:root;Q.push(x->ch[c]);
41                 } else x->ch[c]=x==root?root:x->fail->ch[c];
42             }
43         } return;
44     }
45     int query(char*s,int id){
46         int countn=0;node*x=root;
47         for(int i=0;s[i];i++){
48             int c=s[i];x=x->ch[c];
49             for(node*p=x;p&&p->cnt;p=p->fail) ans[countn++]=p->cnt;
50         }
51         if(countn){
52             sort(ans,ans+countn);
53             printf("web %d: %d",id,ans[0]);
54             for(int i=1;i<countn;i++) if(ans[i]!=ans[i-1])
55                 printf(" %d",ans[i]);
56             puts("");
57         }
58         return countn>0;
59     }
60 }sol;
61 inline int read(){
62     int x=0,sig=1;char ch=getchar();
63     while(!isdigit(ch)){if(ch=='-')sig=-1;ch=getchar();}
64     while(isdigit(ch))x=10*x+ch-'0',ch=getchar();
65     return x*=sig;
66 }
67 inline void write(int x){
68     if(x==0){putchar('0');return;}if(x<0)putchar('-'),x=-x;
69     int len=0,buf[15];while(x)buf[len++]=x%10,x/=10;
70     for(int i=len-1;i>=0;i--)putchar(buf[i]+'0');return;
71 }
72 char s[205],t[10005];
73 void init(){
74     int T,n=read(),m,sum=0;sol.init();
75     for(int i=1;i<=n;i++){
76         scanf("%s",s);
77         sol.insert(s,i);
78     }
79     sol.getfail();m=read();
80     for(int i=1;i<=m;i++){
81         scanf("%s",&t);
82         sum+=sol.query(t,i);
83     }
84     printf("total: %d
",sum);
85     return;
86 }
87 void work(){
88     return;
89 }
90 void print(){
91     return;
92 }
93 int main(){init();work();print();return 0;}
原文地址:https://www.cnblogs.com/chxer/p/4556667.html