[CareerCup][Google Interview] 构造最大数

Given an array of elements find the largest possible number that can 

be formed by using the elements of the array. 
eg: 10 9 
ans: 910 
2 3 5 78 
ans: 78532 
100 9 
ans: 9100

http://www.careercup.com/question?id=9334650

把字符串排个序,比较方法是循环比较各个字符,如果对应位的字符大于另一个字符串的对应位则返回true,否则false。思想就是类似于要把尽可能大的数位放在更高位。

 1 #include <iostream>
 2 #include <string>
 3 #include <vector>
 4 #include <algorithm>
 5 using namespace std;
 6 
 7 bool comp(const string &lhs, const string &rhs)
 8 {
 9     int len = max(lhs.size(), rhs.size());
10 
11     for(int i = 0; i < len; i++)
12     {
13         int lIndex = i % lhs.size();
14         int rIndex = i % rhs.size();
15         if (lhs[lIndex] > rhs[rIndex])
16             return true;
17         else if (lhs[lIndex] < rhs[rIndex])
18             return false;
19     }
20 
21     return true;
22 }
23 
24 string solve(vector<string> &a)
25 {
26     sort(a.begin(), a.end(), comp);
27 
28     string s;
29 
30     for(int i = 0; i < a.size(); i++)
31         s = s + a[i];
32 
33     return s;
34 }
35 
36 int main()
37 {
38     vector<string> a;
39     a.push_back("10");
40     a.push_back("9");
41     cout << solve(a) << endl;
42 
43     vector<string> b;
44     b.push_back("2");
45     b.push_back("3");
46     b.push_back("5");
47     b.push_back("78");
48     cout << solve(b) << endl;
49 
50     vector<string> c;
51     c.push_back("100");
52     c.push_back("9");
53     cout << solve(c) << endl;
54 }
原文地址:https://www.cnblogs.com/chkkch/p/2744514.html