sql 查询条件为拼接字符串 不能使用IN 使用patindex查询结果集

题目: 求组织机构ID在('5dc8de20-9f2f-465e-afcc-f69abecaee50','63549b63-1e0d-4269-98f4-013869d7f211','f7316bf3-38e9-47d4-ab95-8c702b468a2e','61e381d1-c8fc-4276-97e0-3f1b6a0356f5') 中的所有机构。

错误写法:

select * from dd_Report where 1=1 and
OrganizationID in
('5dc8de20-9f2f-465e-afcc-f69abecaee50','63549b63-1e0d-4269-98f4-013869d7f211','f7316bf3-38e9-47d4-ab95-8c702b468a2e','61e381d1-c8fc-4276-97e0-3f1b6a0356f5')
and ReportType='1' and DeleteMark =' 1'

将无法查到(63549b63-1e0d-4269-98f4-013869d7f211,5dc8de20-9f2f-465e-afcc-f69abecaee50)这条记录

正确写法:

思路:求OrganizationID与('5dc8de20-9f2f-465e-afcc-f69abecaee50','63549b63-1e0d-4269-98f4-013869d7f211','f7316bf3-38e9-47d4-ab95-8c702b468a2e','61e381d1-c8fc-4276-97e0-3f1b6a0356f5') 的交集数量。

select *
from dd_Report 
where 1=1 and ReportType='1' and DeleteMark =' 1' and

dbo.splitstring('''' + replace(OrganizationID,',',''',''') + '''',

'''5dc8de20-9f2f-465e-afcc-f69abecaee50'',''63549b63-1e0d-4269-98f4-013869d7f211'',''f7316bf3-38e9-47d4-ab95-8c702b468a2e'',''61e381d1-c8fc-4276-97e0-3f1b6a0356f5''' 
) >0

创建函数

 1 USE [CT_DD]
 2 GO
 3 /****** Object: UserDefinedFunction [dbo].[f_splitSTR] Script Date: 05/20/2016 11:35:44 ******/
 4 SET ANSI_NULLS ON
 5 GO
 6 SET QUOTED_IDENTIFIER ON
 7 GO
 8 ALTER FUNCTION [dbo].[f_splitSTR](
 9 @s varchar(max), --待分拆的字符串
10 @split varchar(10) --数据分隔符
11 )RETURNS @re TABLE(col varchar(100))
12 AS
13 BEGIN
14 DECLARE @splitlen int
15 SET @splitlen=LEN(@split+'a')-2
16 WHILE CHARINDEX(@split,@s)>0
17 BEGIN
18 INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
19 SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,'')
20 END
21 INSERT @re VALUES(@s)
22 RETURN
23 END
View Code
  •  1 USE [CT_DD]
     2 GO
     3 /****** Object:  UserDefinedFunction [dbo].[splitstring]    Script Date: 05/20/2016 11:38:43 ******/
     4 SET ANSI_NULLS ON
     5 GO
     6 SET QUOTED_IDENTIFIER ON
     7 GO
     8 ALTER function [dbo].[splitstring]
     9 (
    10 @str1 varchar(max),
    11 @str2 varchar(max)
    12 )
    13 returns  int
    14  
    15 begin 
    16 declare @num int;set @num=0;
    17  
    18 select @num=COUNT(1) from  f_splitSTR (@str1,',') temp where col in  (select * from  f_splitSTR (@str2,',') temp2)
    19 
    20  return @num;
    21  
    22 end
    View Code

输出结果: 

原文地址:https://www.cnblogs.com/chiyueqi/p/5512036.html