PAT甲题题解-1125. Chain the Ropes (25)-贪心水题

贪心水题,每次取最短的两个绳子合并,长度缩减成一半

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string.h>
#include <string>
#include <map>
using namespace std;
const int maxn=10000+5;
int a[maxn];
int main()
{
    int n;
    scanf("%d",&n);
    for(int i=0;i<n;i++)
        cin>>a[i];
    sort(a,a+n);
    float lastlen=a[0];
    for(int i=1;i<n;i++){
        lastlen=(lastlen+a[i])/2;
    }
    printf("%d
",(int)lastlen);
    return 0;
}
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原文地址:https://www.cnblogs.com/chenxiwenruo/p/6506444.html