2019.12.17基佬出的一道题

代码如下：
 1 # -*- coding: utf-8 -*-
 2 """
 3 @File:hz.py    
 4 @E-mail:chenshengkai@vip.qq.com
 5 @Time:2019-12-17 10:28 
 6 @Author:Nobita   
 7 @Version:1.0   
 8 @Desciption:None
 9 """
10 
11 from datetime import datetime
12 
13 '''
14 题目：
15 一个数据集合,存有多个这种字典{"time":"2019-04-16 08:23:40"}
16 对同一天时间的筛选出最早的一条,就是每天只有一条数据，
17 如果出现多条/就取当天最早的,筛选完后对数据从小到大排序,
18 数据自己伪造。
19 '''
20 dict_data = {
21     "time1": "2019-04-01 06:22:41",
22     "time2": "2019-04-01 06:22:41",
23     "time3": "2019-04-01 09:23:40",
24     "time4": "2019-04-01 08:24:45",
25     "time5": "2019-04-02 08:23:40",
26     "time6": "2019-04-02 13:25:41",
27     "time7": "2019-04-03 08:23:40",
28     "time8": "2019-04-03 08:23:40",
29     "time9": "2019-04-04 08:23:40",
30     "time10": "2019-04-05 05:21:41",
31     "time11": "2019-04-05 11:23:40",
32     "time12": "2019-04-05 09:15:15",
33     "time13": "2019-04-06 08:12:12",
34     "time14": "2019-04-07 08:57:41",
35     "time15": "2019-04-11 09:21:11",
36     "time16": "2019-04-12 08:23:40"
37 }
38 
39 if __name__ == '__main__':
40     dict_list = dict()
41     # 循环获取字符串，并进行初步的日期处理
42     for v in dict_data.values():
43         data = datetime.strptime(v, '%Y-%m-%d %H:%M:%S')
44         data_str = str(data.date())
45         if data_str not in dict_list:
46             dict_list[data_str] = list()
47         dict_list[data_str].append(v)
48         dict_list[data_str].sort(reverse=False)
49     # 获取每个日期第一个并排序
50     result = [v[0] for v in dict_list.values()]
51     result.sort(reverse=False)
52     print(result)