String IPV4_REGEX = "\A(25[0-5]|2[0-4]\d|[0-1]?\d?\d)(\.(25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3}\z"; List<String> list = Arrays.asList(split); for (String item : list) { if(Pattern.matches(IPV4_REGEX, item) == false){ throw new Exception("存在不合规的ip"); } }
类似于上面的IPV4_REGEX