javascript---【利用函数翻转任意数组】

  function sort(arr) {
            for (var i = 0; i < arr.length - 1; i++) {
                for (var j = 0; j < arr.length - i - 1; j++) {
                    if (arr[j] > arr[j + 1]) {
                        var temp = arr[j];
                        arr[j] = arr[j + 1];
                        arr[j + 1] = temp;
                    }
                }
            }
            return arr;
        }
        var arr1 = sort([1, 4, 2, 9]);
        console.log(arr1);
        var arr2 = sort([11, 7, 22, 999]);
        console.log(arr2);
原文地址:https://www.cnblogs.com/chenhaiyun/p/14345719.html