js 14位字符串 转日期

const pattern = /(d{4})(d{2})(d{2})(d{2})(d{2})(d{2})/;
const newDate = new Date(timeEnd.replace(pattern, '$1-$2-$3 $4:$5:$6'));

  

原文地址:https://www.cnblogs.com/chendaoyin/p/10291963.html