冲刺Offer

https://www.nowcoder.net/practice/435fb86331474282a3499955f0a41e8b?tpId=13&tqId=11191&tPage=2&rp=2&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking

题目描述

输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。
 

解答:

用递归的话,比较简单。
 
/*
struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
    TreeNode(int x) :
            val(x), left(NULL), right(NULL) {
    }
};*/
class Solution {
public:
    int TreeDepth(TreeNode* pRoot)
    {
        if (pRoot == NULL) return 0;
        
        int ld = TreeDepth(pRoot->left);
        int rd = TreeDepth(pRoot->right);
        return (ld > rd)?(ld + 1):(rd + 1);
    }
};
原文地址:https://www.cnblogs.com/charlesblc/p/8443499.html