LeetCode : Merge Sorted Array

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
合并两个有序数组,考虑从后往前进行存储

class Solution {
public:
    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
        int end = m+n-1;
        m--;
        n--;
        while(m>=0&&n>=0)
        {
            if(nums1[m]<nums2[n])
            {
                nums1[end--] = nums2[n--];
            }
            else
            {
                nums1[end--] = nums1[m--];
            }
        }
        while(n>=0)
        {
            nums1[end--] = nums2[n--];
        }
    }
};
原文地址:https://www.cnblogs.com/chankeh/p/6850062.html