LeetCode : Sqrt(x)

Implement int sqrt(int x).

Compute and return the square root of x.

class Solution {
public:
    int mySqrt(int x) {
        long r = x;
        while (r*r > x)
            r = (r + x/r) / 2;
        return r; 
    }
};
原文地址:https://www.cnblogs.com/chankeh/p/6850047.html