leetcode Search in Rotated Sorted Array

代码:

 1 #include<iostream>
 2 #include<vector>
 3 
 4 using namespace std;
 5 
 6 int search(vector<int>& nums, int target) 
 7 {
 8     int L = nums.size();
 9     int k = 0;
10     int min = nums[0];
11     for (int i = 1; i < L; i++)
12     {
13         if (nums[i] < min)
14         {
15             min = nums[i];
16             k = i;
17         }
18     }
19     int left, right;
20     if (target>nums[L - 1])
21     {
22         left = 0;
23         right = k - 1;
24     }
25     else
26     {
27         left = k;
28         right = L - 1;
29     }
30     while (left <= right)
31     {
32         int mid = (left + right) / 2;
33         if (target < nums[mid])
34         {
35             right = mid - 1;
36         }
37         else if (target > nums[mid])
38         {
39             left = mid + 1;
40         }
41         else
42         {
43             return mid;
44         }
45     }
46     return -1;
47 }
48 
49 int main()
50 {
51     vector<int> a = {4, 5, 6, 7, 0};
52     cout << search(a, 0) << endl;
53 }
原文地址:https://www.cnblogs.com/chaiwentao/p/4495345.html