hdu2084 数塔 DP

数字三角形,DP裸题

 1 #include<stdio.h>
 2 #include<string.h>
 3 #define max(a,b) (a)>(b)?a:b
 4 
 5 int g[101][101],dp[101][101];
 6 
 7 int max1(int i,int j){
 8     return i>j?i:j;
 9 }
10 
11 int main(){
12     int C;
13     while(scanf("%d",&C)!=EOF){
14         for(int q=1;q<=C;q++){
15             int N;
16             scanf("%d",&N);
17             memset(dp,0,sizeof(dp));
18             int i,j;
19             for(i=1;i<=N;i++){
20                 for(j=1;j<=i;j++){
21                     scanf("%d",&g[i][j]);
22                 }
23             }
24             dp[1][1]=g[1][1];
25             for(i=2;i<=N;i++){
26                 for(j=1;j<=i;j++){
27                     if(j==1)dp[i][j]=dp[i-1][j]+g[i][j];
28                     else if(j==i)dp[i][j]=dp[i-1][j-1]+g[i][j];
29                     else dp[i][j]=max1(dp[i-1][j-1],dp[i-1][j])+g[i][j];
30                 }
31             }
32             int m=dp[N][1];
33             for(i=2;i<=N;i++)if(dp[N][i]>m)m=dp[N][i];
34             printf("%d
",m);
35         }
36 
37     }
38     return 0;
39 }
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原文地址:https://www.cnblogs.com/cenariusxz/p/6578157.html