cf734 E. Anton and Tree

这个题的题意还是很劲的。搞了好久才知道是怎么变得。

(假设已经缩好了点,每次边中间颜色不同的,然后和就和他外面的相同,继续再变这个大的,依次类推,最多就是树的直径D/2)

(还是英语水平太弱了(吐槽++,数学考得还没英语高,还是找个地方撞死吧2333))

  1 #include<bits/stdc++.h>
  2 #define lowbit(x) x&(-x) 
  3 #define LL long long 
  4 #define N 200005
  5 #define M 1000005
  6 #define mod 1000000007LL
  7 #define inf 0x7ffffffff
  8 using namespace std;
  9 inline int ra()
 10 {
 11     int x=0,f=1; char ch=getchar();
 12     while (ch<'0' || ch>'9'){if (ch=='-') f=-1; ch=getchar();}
 13     while (ch>='0' && ch<='9'){x=x*10+ch-'0'; ch=getchar();}
 14     return x*f;
 15 }
 16 struct node{
 17     int next,to;
 18 }re[N<<1],e[N<<1];
 19 int head[N],hd[N],cnt,recnt;
 20 void insert(int x, int y)
 21 {
 22     e[++cnt].to=y;
 23     e[cnt].next=head[x];
 24     head[x]=cnt;
 25 }
 26 void reinsert(int x, int y)
 27 {
 28     re[++recnt].to=y;
 29     re[recnt].next=hd[x];
 30     hd[x]=recnt;
 31 }
 32 int ans,sum[N],belong[N],mx[N],sec[N],n,deep[N];
 33 bool col[N];
 34 void dfs(int x, int num)
 35 {
 36     belong[x]=num;
 37     for (int i=head[x];i;i=e[i].next)
 38     {
 39         if (belong[e[i].to]) continue;
 40         if (col[e[i].to]==col[x]) dfs(e[i].to,num);
 41     }
 42 }
 43 void rebuild()
 44 {
 45     for (int i=1; i<=n; i++)
 46     {
 47         for (int j=head[i];j;j=e[j].next)
 48         {
 49             if (belong[e[j].to]==belong[i]) continue;
 50             reinsert(belong[i],belong[e[j].to]);
 51         }
 52     }
 53 }
 54 void dfs1(int x, int fa)
 55 {
 56     deep[x]=1; int mx=0,sc=0;
 57     for (int i=hd[x];i;i=re[i].next)
 58     {
 59         if (re[i].to==fa) continue;
 60         dfs1(re[i].to,x);
 61         deep[x]=max(deep[x],deep[re[i].to]+1);
 62         if (mx==deep[re[i].to]) sc=mx;
 63         if (mx<deep[re[i].to]) sc=mx,mx=deep[re[i].to];
 64         if (mx>deep[re[i].to]) sc=max(sc,deep[re[i].to]);
 65     }
 66     ans=max(ans,max(deep[x],mx+sc+1));
 67 }
 68 int main()
 69 {
 70     n=ra();
 71     for (int i=1; i<=n; i++) col[i]=ra();
 72     for (int i=1; i<n; i++)
 73     {
 74         int x=ra(),y=ra();
 75         insert(x,y);
 76         insert(y,x);
 77     }
 78     int tot=0;
 79     for (int i=1; i<=n; i++)
 80         if (!belong[i]) dfs(i,++tot);
 81     rebuild();
 82     dfs1(1,0);
 83     cout<<ans/2;
 84     return 0;
 85 } //一开始没看懂题意2333,以为好水
 86 /*#include<bits/stdc++.h>
 87 #define lowbit(x) x&(-x) 
 88 #define LL long long 
 89 #define N 200005
 90 #define M 1000005
 91 #define mod 1000000007LL
 92 #define inf 0x7ffffffff
 93 using namespace std;
 94 inline int ra()
 95 {
 96     int x=0,f=1; char ch=getchar();
 97     while (ch<'0' || ch>'9'){if (ch=='-') f=-1; ch=getchar();}
 98     while (ch>='0' && ch<='9'){x=x*10+ch-'0'; ch=getchar();}
 99     return x*f;
100 }
101 struct node{
102     int next,to;
103 }e[N<<1];
104 int head[N],cnt;
105 bool vis[N],col[N];
106 inline void insert(int x, int y)
107 {
108     e[++cnt].to=y;
109     e[cnt].next=head[x];
110     head[x]=cnt;
111 }
112 void dfs(int x, int fa)
113 {
114     vis[x]=1;
115     for (int i=head[x];i;i=e[i].next)
116     {
117         if (e[i].to==fa || col[e[i].to]!=col[x] || vis[e[i].to]) continue;
118         dfs(e[i].to,x);
119     }
120 }
121 int n,ans1,ans0;
122 int main()
123 {
124     n=ra();
125     for (int i=1; i<=n; i++) col[i]=ra();
126     for (int i=1; i<n; i++)
127     {
128         int x=ra(),y=ra();
129         insert(x,y);
130         insert(y,x);
131     }
132     for (int i=1; i<=n; i++)
133         if (col[i]==0 && !vis[i]) ++ans0,dfs(i,0);
134     memset(vis,0,sizeof(vis));
135     for (int i=1; i<=n; i++)
136         if (col[i]==1 && !vis[i]) ++ans1,dfs(i,0);
137     cout<<min(ans1,ans0);
138     return 0;
139 }*/
原文地址:https://www.cnblogs.com/ccd2333/p/6288776.html