Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the coin into the left, the underneath or the left-underneath blank space.The person who can't make a move will lose the game. kiki plays it with ZZ.The game always starts with kiki. If both play perfectly, who will win the game?
Input
Input contains multiple test cases. Each line contains two integer n, m (0<n,m<=2000). The input is terminated when n=0 and m=0.
Output
If kiki wins the game printf "Wonderful!", else "What a pity!".
Sample Input
5 3
5 4
6 6
0 0
Sample Output
What a pity!
Wonderful!
Wonderful!
题意倒是很容易理解，ac代码也是很短，但是理解确实不易，我自己归纳出来的结论，但是证明不了！
说的好的也就这一个了：http://www.cnblogs.com/MiYu/archive/2010/08/18/1802685.html
再贴个代码，记录下！
#include <stdio.h> #include <string.h> int main() { int i,j,n,m; while(scanf("%d%d",&n,&m)!=EOF&&n||m) { if(n*m%2 != 0)printf("What a pity! "); else printf("Wonderful! "); } return 0; }