js 删除节点,jquery遍历通过内容定位节点

$(".class1 .class2").each(function (index, item) {
            var gettedValue = $(item).find(".class3").text();           
            if(gettedValue == forFindContent){              
                //do something
            } 
});

//删除节点:

var a = document.querySelectorAll("div[id=2]");    
for(var i=0;i<a.length;i++){
         a[i].parentNode.removeChild(a[i])
}

//查找兄弟节点:

//get p value
<div id ='2'>1</div>
<p>1</p>
//
var o = document.querySelector(div);
var p = o.nextElementSibling.innerText()
原文地址:https://www.cnblogs.com/cbugs/p/9507762.html