树状数组求逆序对模板

#include<iostream>
#include<algorithm>
using namespace std;
const int maxn=40010;
int n,ans,a[maxn],b[maxn],c[maxn],s[maxn];
int lowbit(int x)
{
    return x&(-x);
}
void add(int x)
{
    for(int i=x;i<=n;i+=lowbit(i))
    c[i]++;
}
int getsum(int x)
{
    int ans=0;
    for(int i=x;i>=1;i-=lowbit(i))
    ans+=c[i];
    return ans;
}
int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    cin>>a[i],s[i]=a[i];
    sort(s+1,s+n+1);
    int tot=unique(s+1,s+n+1)-s-1;
    for(int i=1;i<=n;i++)
    {
        int pos=lower_bound(s+1,s+tot+1,a[i])-s;
        b[i]=pos;
    }
    for(int i=n;i>=1;i--)
    {
        ans+=getsum(b[i]);
        add(b[i]+1);
    }
    cout<<ans;
    return 0;
}
原文地址:https://www.cnblogs.com/cax1165/p/6070964.html