Feed Ratios USACO 3.2

额,要求都要最小,4重循环直接搜索即可...

 1 /*
 2 
 3 ID: hubiao cave
 4 
 5 PROG: ratios
 6 
 7 LANG: C++
 8 
 9 */
10 
11 
12 
13 
14 #include<iostream>
15 
16 #include<fstream>
17 
18 #include<string>
19 
20 using namespace std;
21 
22 
23 bool CanFit(int,int,int,int);
24 int arry[12];
25 int main()
26 
27 {
28 
29 
30     ifstream fin("ratios.in");
31 
32     ofstream fout("ratios.out");
33     for(int i=0;i<12;i++)
34         fin>>arry[i];
35 
36     for(int i=0;i<=100;i++)
37         for(int j=0;j<=100;j++)
38           for(int m=0;m<=100;m++)
39              for(int n=0;n<=100;n++)
40     {
41         if(CanFit(i,j,m,n))
42         {
43             fout<<i<<" "<<j<<" "<<m<<" "<<n<<endl;
44             return 0;
45         }
46     }
47     fout<<"NONE"<<endl;
48     return 0;
49 
50 
51 }
52 bool CanFit(int i,int j,int m,int n)
53 {
54     if(!i&&!j&&!m)
55         return false;
56     int sum1=i*arry[3]+j*arry[6]+m*arry[9];
57     int sum2=i*arry[4]+j*arry[7]+m*arry[10];
58     int sum3=i*arry[5]+j*arry[8]+m*arry[11];
59 
60     if(sum1==n*arry[0]&&sum2==n*arry[1]&&sum3==n*arry[2])
61         return true;
62     return false;
63 }
原文地址:https://www.cnblogs.com/cavehubiao/p/3356006.html