30 Day Challenge Day 15 | Leetcode 257. Binary Tree Paths

题解

Easy | DFS

class Solution {
public:
    vector<string> binaryTreePaths(TreeNode* root) {
        vector<string> paths;
        dfs(root, "", paths);
        return paths;
    }
    
    void dfs(TreeNode* node, string path, vector<string>& paths) {
        if(!node) return;
        
        if(!node->left && !node->right) {
            path += to_string(node->val);
            paths.push_back(path);
            return;
        }
        
        path += to_string(node->val) + "->";

        dfs(node->left, path, paths);
        dfs(node->right, path, paths);
    }
};
原文地址:https://www.cnblogs.com/casperwin/p/13754540.html