Silverlight中Treeview中判断当前节点是否含有父节点

public bool isPareNull(TreeViewItem CurrItem)
{
  bool boolPareNote = false;
  try
  {
    if (CurrItem.Parent != null)
    boolPareNote = true;
  }
  catch (Exception)
  {
    throw;
  }
  return boolPareNote;
}

原文地址:https://www.cnblogs.com/caok168/p/2563343.html