判断一个数的质因子个数

#include<iostream>
using namespace std;
int Prim( int n)
{
    int i=2,cnt=0;
    while(n>0&&n>=i)
    {
        if(n%i==0)
        {
            cnt++;
            while(n%i==0)
            {
                n=n/i;
            }
        }
        i++;
    }
    return cnt;
}
int main()
{
    int n;
    while(cin>>n)
    {
        cout<<Prim(n)<<endl;
    }
    return 0;
}
原文地址:https://www.cnblogs.com/calmwithdream/p/5559339.html